Contents

# 2019 WAEC GCE FURTHER MATHEMATICS ANSWERS

F/MATHS OBJ

1-10: ABCCBCDBDC

11-20: DBDCADABCD

21-30: BCBBCDCCCD

# 31-40: CBDABBAACA

(1)

Digits 1,2,4,5,6

The first digit can be formed in 5 ways

The last digit can be formed in 2 ways since no repition take place

The second digit can be formed in 3 ways

The third digit can be formed in 2 ways

The fourth in 1 way

Total ways

5*3*2*1*2

# Answer= 60 ways

(2)

ar^4-1=54

ar^3=54————(1)

ar^6-1=486

ar^5=486————(2)

Divide equation (2) by (1)

ar^5/ar^3=496/54

r²=9

Square root both sides

r=√9

r=3//

Substitute r=3 on equation (1)

a(3)³=54

a(27)=54

Divide both sides by 27

a=54/27

a=2//

3rd term

ar^n-1

2(3)³–¹

2(3)²

2(9)

# 18//

(4)

y=3x²+4x–1 —————(1)

y+∆y=3(x+∆x)² + 4(x+∆x) –1 ————(2)

Subtract (1) from (2)

∆y=3(x+∆x)² + 4(x+∆x) –1–(3x²+4x–1)

=3(x²+2x∆x+∆x²) +4(x+∆x) –1–(3x²+4x–1)

=3x²+6x∆x+3∆x²+4x+4∆x–1–3x²–4x+1

∆y=6x∆x+3∆x²+4∆x

∆y/∆x=6x∆x3∆x²+4∆x/∆x

∆y/∆x=(6x+3∆x+4)∆x/∆x

Lim ∆y/∆x=∆y/∆x=6x+3(0)+4

∆x→0

# ∆y/∆x=6x+4

(5) sample space

TABULATE

★| 1 2 3 4 5 6

1 | 11 12 13 14 15 16

2 | 21 22 23 24 25 26

3 | 31 32 33 34 35 36

4 | 41 42 43 44 45 46

5 | 51 52 53 54 55 56

6 | 61 62 63 64 65 66

TABULATE

- | 1 2 3 4 5 6

1| 2 (3) 4 5 (6) 7

2| (3) 4 5 (6) 7 8

3| 4 5 (6) 7 8 (9)

4| 5 (6) 7 8 (9) 10

5| (6) 7 8 (9) 10 11

6| 7 8 (9) 10 11 (12)

probability of

(a) multiple of 3=12/36=1/3