Table of Contents

## Waec Mathematics Expo 2020 | Waec Maths Runs 2020

Waec Mathematics Expo 2020 | Waec Maths Runs 2020**How to Get the correct 2020 WAEC mathematics Runz Qu****estions/Answers as we only offered Legit and verified WAEC mathematics correct answer here. get complete WAEC mathematics objective and theory/essay answers As Text Message, Password Link, and WhatsApp Message Midnight Before Exam. 100% Assured!**

The 2020 WAEC August/September General Mathematics (Obj & Essay) Solution Expo Questions and Answer are around the corner, 2020 WAEC Mathematics expo (runs) questions and answers, directly from WAEC Internal exam head office. This is the correct, legit 2020/2021 WAEC Mathematics questions and answers 6hours or midnight before exam On https://funloaded.org.ng

[njwa_button id=”29331″]

**RECOMMENDED:**

*WAEC Mathematics Symbol for Those That Subscribe for 2020 Exam Runz**Factorization of Quadratic Equation (Factoring Calculator)**Simultaneous Equations: Solved Examples and Shortcut Tricks**Evaluate 2115 base seven Divided by 12 base seven**2020/2021 Waec Expo | 2020 Waec Runs (Runz) Free Waec Expo/Runs**Final International WAEC Timetable for 2020 School Candidates*

**WAEC MATHEMATICS EXAMINATION HAS BEEN SCHEDULED TO TAKE PLACE ON**

**Monday, 17 ^{th} August 2020**

- General Mathematics (Essay) › 8:30 am – 11:00 am
- General Mathematics (Objective) › 2:00 pm – 3:30 pm

**HOW TO SUBSCRIBE FOR WAEC MATHEMATICS EXPO**

↔Direct SMS: #1500 MTN CARD

↔Online PIN:- #1000 MTN CARD

↔WhatsApp Plan:- #1000 MTN CARD

**Direct SMS MEANS:** all answers( & Essay and Objective) will come directly to ur phone as SMS.

**Online PIN MEANS **the Pin-to access our answers online.

**Online Answer Link: https://funloaded.net **PASSWORD IS: **0911**

*DON’T THINK FREE ANSWER WILL BE POSTED HERE NEXT TIME, SUBSCRIBE FOR THE NEXT PAPER NOW TO AVOID DISAPPOINTMENT. *

**MATHS OBJ**

1-10 :CBCDACDCCD

11-20 :AADBDACBBC

21-30 :BDDABDADAD

31-40 :CDACCCCCDA

41-50 :BBBCDCACDB

Completed👏🏽✌🏽

=====================================

**WAEC 2020 MATHEMATICS THEORY ANSWERS**

===========================================

**(1a)**

Given A={2,4,6,8,…}

B={3,6,9,12,…}

C={1,2,3,6}

U= {1,2,3,4,5,6,7,8,9,10}

A’ = {1,3,5,7,9}

B’ = {1,2,4,5,7,8,10}

C’ = {4,5,7,8,9,10}

A’nB’nC’ = {5, 7}

**(1b)**

Cost of each premiere ticket = $18.50

At bulk purchase, cost of each = $80.00/50 = $16.00

Amount saved = $18.50 – $16.00

=$2.50

=================

**(2ai)**

P = (rk/Q – ms)⅔

P^3/2 = rk/Q – ms

rk/Q = P^3/2 + ms

Q= rk/P^3/2 + ms

**(2aii)**

When P =3, m=15, s=0.2, k=4 and r=10

Q = rk/p^3/2 + ms = 10(4)/(3)^3/2 + (15)(0.2)

= 40/8.196 = 4.88(1dp)

**(2b)**

x + 2y/5 = x – 2y

Divide both sides by y

X/y + 2/5 = x/y – 2

Cross multiply

5(x/y) – 10 = x/y + 2

5(x/y) – x/y = 2 + 10

4x/y = 12

X/y = 3

X : y = 3 : 1

=====================

**(3a)**

Diagram

CBD = CDB (base angles an scales D)

BCD+CBD+CDB=180° (Sum of < in a D)

2CDB+BCD=180°

2CDB+108°=180°

2CDB=180°-108°=72°

CDB=72/2=36°

BDE=90°(Angle in semi circle)

CDE=CDB+BDE

=36°+90

=126

**(3b)**

(Cosx)² – Sinx given

(Sinx)² + Cosx

Using Pythagoras theory thrid side of triangle

y²= 1²+√3

y²= 1+ 3=4

y=√4=2

(Cosx)² – sinx/(sinx)² + cosx

(1/2)² – √3/2/

(√3/2)² + 1/2 = 1/4 – √3/2 = 1-2√3/4

3/4+1/2 = 3+2/4

=1-2√3/4 * 4/5

=1-2√3/5

=====================

**(4a)**

Given: r : l = 2 : 5 (ie l = 5/2r)

Total surface area of cone =πr² + url

224π = π(r² + r(5/2r))

224 = r² + 5/2r²

224 = 7/2r²

7r² = 448

r² = 448/7 = 64

r = root 64 = 8.0cm

**(4b)**

L = 5/2r = 5/2 × 8 = 20cm

Using Pythagoras theorem

L² = r² + h²

h² = l² – r²

h² = 20² – 8²

h² = (20 + 8)(20 – 8)

h² = 28 × 12

h = root28×12

h = 18.33cm

Volume of cone = 1/3πr²h

= 1/3 × 22 × 7 × 8² × 18.33

=1229cm³

=======================

**(5a)**

Total income = 32+m+25+40+28+45

=170+m

PR(²)=m/170+m = 0.15/1

M=0.15(170+m)

M=25.5+0.15m

0.85m/0.85=25.5/0.85

M=30

**(5b)**

Total outcome = 170 + 30 = 200

**(5c)**

PR(even numbers) = 30+40+50/200

=115/200 = 23/40

==========================

**=== SECTION B ====**

================================

**(7a)** Click here to view image

Using Pythagoras theorem, l²=48² + 14²

l²=2304 + 196

l²=2500

l=√2500

l=50m

Area of Cone(Curved) =πrl

Area of hemisphere=2πr²

Total area of structure =πrl + 2πr²

=πr(l + 2r)

=22/7 * 14 [50 + 2(14)]

=22/7 * 14 * 78

=3432cm²

~3430cm² (3 S.F)

**(b)**

let the percentage of Musa be x

Let the percentage of sesay be y

x + y=100 ——————-1

(x – 5)=2(y – 5)

x – 5=2y – 10

x – 2y=-5 ——————-2

Equ (1) minus equ (2)

y – (-2y)=100 – (-5)

3y=105

y=105/3

y=35

Sesay’s present age is 35years

====================================

**(8a)**

Let Ms Maureen’s Income = Nx

1/4x = shopping mall

1/3x = at an open market

Hence shopping mall and open market = 1/4x + 1/3x

= 3x + 4x/12 = 7/12x

Hence the remaining amount

= X-7/12x = 12x-7x/12 =5x/12

Then 2/5(5x/12) = mechanic workshop

= 2x/12 = x/6

Amount left = N225,000

Total expenses

= 7/12x + X/6 + 225000

= Nx

7x+2x+2,700,000/12 =Nx

9x + 2,700,000 = 12x

2,700,000 = 12x – 9x

2,700,000/3 = 3x/3

X = N900,000

(ii) Amount spent on open market = 1/3X

= 1/3 × 900,000

= N300,000

(8b)

T3 = a + 2d = 4m – 2n

T9 = a + 8d = 2m – 8n

-6d = 4m – 2m – 2n + 8n

-6d = 2m + 6n

-6d/-6 = 2m+6n/-6

d = -m/3 – n

d = -1/3m – n

====================================

**(9a)**

Draw the triangle

(9b)

(i)Using cosine formulae

q² = x² + y² – 2xycosQ

q² = 9² + 5² – 2×9×5cos90°

q² = 81 + 25 – 90 × 0

q² = 106

q = square root 106

q = 10.30 = 10km/h

Distance = 10 × 2 = 20km

(ii)

Using sine formula

y/sin Y = q/sin Q

5/sin Y = 10.30/sin 90°

Sin Y = 5 × sin90°/10.30

Sin Y = 5 × 1/10.30

Sin Y = 0.4854

Y = sin‐¹(0.4854), Y = 29.04

Bearing of cyclist X from y

= 90° + 19.96°

= 109.96° = 110°

(9c)

Speed = 20/4, average speed = 5km/h

==========================================================

**HOW TO SUBSCRIBE WITH MTN CARD**

**Send The Following details:-?**

ii) Subject

**(Mathematics)**.

iii) The Amount you sent

iv) Package (E.g I want it As SMS)

v) Your Phone number

**Send it to 08032773749**

[njwa_button id=”29331″]

**SUBSCRIPTION FOR WAEC MATHEMATICS (GHANA, GAMBIA, LIBERIA, AND SIERRA LEONE) PER SUBJECT PAYMENT IS AVAILABLE NOW**

NOTE:SIERRALEONE, GHANA, GAMBIA, LIBERIA, GUINEA 2020 PRIVATE WAEC GCE JAN/FEB CANDIDATES/STUDENTS SHOULD MESSAGE US ON WHATSAPP FOR THEIR SUBSCRIPTION PAYMENT = +2348032773749.

↔Direct SMS:50GHC FOR GHANA | 50,000SL FOR S-LEONE

↔Online PIN:-30GHC FOR GHANA | 30,000SL FOR S-LEONE

↔WhatsApp Plan:-30GHC FOR GHANA | 30,000SL FOR S-LEONE

[MESSAGE US ON WHATSAPP NOW FOR YOUR MODE OF PAYMENT FOR ALL SUBJECT: NOTE, ONLY SERIOUS STUDENTS PLS]

Always Send Us **Text SMS or WhatsApp to +2348032773749** Of Your Complaint Even When Our Number Is Diverted Or Not Available, Your Message(s) Will Get To Us And We Will Reply You ASAP.

**PLEASE NOTE:** AVOIDING CALLING US & NO SENDING OF FAKE PINS.

*FOR MORE DETAILS AND PROCEDURE CONTACT US ON:*

**– ****08032773749 ****– NIGERIA**

**– +234****8032773749**** – SIERRA LEONE, GHANA GAMBIA & LIBERIA.**

I WISH YOU ALL GOOD LUCK 🤞…

NO PAYMENT NO PAPERS

PAYMENT BEFORE PAPERS

WAEC GENERAL MATHEMATICSSOLUTION

=========================

**Funloaded.org.ng** send all exam expo answer earlier than others

============================