NECO GCE Physics Practical Questions and Answers 2023/2024 | Alternative to Practical Specimen

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NECO GCE Physics practical specimen 2023 questions and answers can be seen here. The NECO GCE Physics practical question paper will be brought in for the exam on Monday 27th November, 2023.

The Physics 1 Practical exam is held from 2.00 pm – 4.00 pm. We are writing this post to show the NECO Physics specimen from the provided yellow paper, NECO Physics practical drawings, and materials that were used in the NECO Physics practical exam past questions and syllabus.

NECO GCE Physics Practical Questions and Answers Expo

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NECO GCE Physics Practical Expo

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NECO GCE Physics Specimen 2023

This is for preparation purposes for candidates writing the examination.

Candidates for the Neco Physics practical will get the usual apparatus and reagents for qualitative work. The Neco Physics practical reagents will include;

(a) You have been provided with a beaker, a set of masses, and other necessary apparatus.

i. Measure and record the internal diameter D of the beaker

ii. Pour some water into the beaker so that it is about half full Measure and record the depth d0 of the water.

iii. Suspend a mass M = 50g on the clamp of a retort stand.

Immerse the mass completely into the water as shown in the diagram above.

iv. Measure and record the new depth di of the water

v. Evaluate d = di – d0

vi. Repeat the procedure for values of M = 100g, 15og, 200g and 250g

vii. In each case measure and record di and also evaluate d = di- do

viii. Tabulate your reading

ix. Plot a graph with M on the vertical anti and d on the horizontal axis

x. Determine the slope, s, of the graph

xi. Evaluate k=4s/PiD2 (Take Pi=22/7)

xii. State two precautions are taken to ensure accurate results.

(b) i. Define the relative density of a body.

ii. An object weighs 2.7 N in air and 1.2 N when completely immersed in water Calculate the relative density of the body.

NECO Physics Practical Answer

2ai)

fo=15cm

2av)

a=60.00cm
b=20.00cm

Hence L=a/b=60.00/20.00
L=3

2avi)

TABULATE
S/N:1,2,3,4,5
b(cm):20.00,25.00,35.00,40.00
a(cm):60.00,37.50,30.00,26.25,24.00
L=a/b:3.00,1.50,1.00,0.75,0.60

2avii)

Slope=Change in L/Change in a
=(3-0.25)/(60-18.6)
=2.75/41.4
=0.006642

2aviii)

S^-1=1/S
=(1/0.0066425cm)
S=15.05
S=15cm

2aix)

PRECAUTIONS

-I ensured all apparatus were in a straight line

-I avoided error because of parallax when reading the metre rule

-I avoided zero error on the metre rule

2bi)

u=10cm
f=15cm
Using 1/v+1/u=1/f
1/f-1/u=1/v
1/v=1/15-1/10
1/v=(2-3)/30
1/v=-1/30
v=-30cm

The characteristics of the image formed are:

-It is virtual

-It is enlarged and magnified ie twice or two times as big as the object m=2

2bii)

The concave mirror mounted in its holder is moved to and fro in front of the screen until a sharp image of the cross wire of the ray box is formed on the screen adjacent to the object.

The distance between the mirror and the screen was measured as 30cm since the radius of curvature r=2fo then half is distance.

2bi)

The characteristics of imaged formed are :

I) It is virtual

ii) It is enlarged or magnified i.e. twice or two times bigger as the object(m=2)

2bII) The concave mirror, mounted in its holder, is moved to and fro in front of them until a sharp image of the cross wire of the ray box is formed on the screen adjacent to the object.

The distance between the mirror and the screen was measured as 30.1cm. Since the radius of the curvature r,=2fo, then half this distance is the focal length of the mirror fo.

Thus focal length was determined to be 15.05cm approximately 15cm

DRAW THE GRAPH of V^-1(v^-1) against R^-1

(3av)

Slope=change inV^-1/Change inR^-1
=(7.6-4.3)/(0.84-0.10)
3.3/0.74
=4.460

(3avi) Intercept=0.385

(3avii)  I=0.385
I^-1=(0.385)^-1
=2.597

Conclusion 

Please note that the answers presented in this post are a guide to the forthcoming General Certificate Examination (GCE). We have prepared it to aid the student in preparing for the practical. If you have any questions about the NECO GCE 2023 Physics Practical questions and answers, kindly let us know in the comment box

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