NECO Chemistry Practical Specimens for 2021/2022 Now Available

NECO Chemistry Practical Specimens

NECO Chemistry Practical Specimens for 2021 June/July Examination (SSCE): National Examination Council of Nigeria [NECO] June/July Internal Senior School Certificate Examination [SSCE] Original/Authentic Official Instructions to Schools Specimens for 2021/2022 Academic Session Now Published [Download in PDF].

This is to inform all candidates who registered for the NECO Examination for 2021/2022 that the Chemistry examination specimens/instruction Areas of Concentrations are now available.

Welcome to the NECO Chemistry Practical Specimens for 2021 Areas of Concentration that you cannot escape [Instructions to Schools, Colleges candidates].

From the available NECO Exam Timetable, the examination is scheduled to hold from 5th July and ends on 16th August 2021.

Other information on the NECO Chemistry Practical Specimens will also be discussed.

Now, you want to know if the NECO Chemistry Practicals Specimens is Out, right?

If yes, then this information is good for you and will enlighten you on that.

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Also Read: Active NECO WhatsApp Group link for 2021/2022 Session Now Available

NECO Chemistry PRACTICAL SSCE Internal Examination Specimens

TITRATION
I. Dilute sodium hydroxide solution
II. Dilute ammonia solution
III. Dilute hydrochloric acid
IV. Dilute trioxonitrate(V)acid
V. Distilled water
VI. Red and blue litmus paper
VII. Barium chloride solution
VIII. Phenolphthalein solution
IX. Methyl orange
X. One boiling tube
XI. Five test tubes
XII. Source of heat
XIII. Wash bottle containing distilled water
XIV. Filtration apparatus

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A simple way to Pass NECO Chemistry 2021 Practical Specimen Examination

As a matter of fact, there are some simple steps you can take in order to pass your exam very easily. These are the tips we shall give below so as to guide you in passing these 2021 NECO Practical questions and provide yourself with correct answers.
  • NECO 2021 syllabus is the very first thing you should think of. If you know the syllabus for Chemistry Practical Specimen, then you can easily know which area to concentrate on. So I recommend that you should get this NECO Syllabus.
  • NECO Past questions on Chemistry practical should come into your mind. Having the past question for any subject helps you to know the manner and the likes of questions you should expect from that subject so as to be able to answer them accordingly.
  • After getting all these items, then the next step is for you to sit down and study this subject effectively and all the questions will be very simple for you.
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NECO Practical Chemistry Questions and Answers

Note: The 2021 NECO Practical Chemistry answers (expo) will be posted for those who subscribed with us alone, Mr. Funloaded has long ago created NECO VIP WhatsApp Group for interested tutors, Principal’s agents, and Teachers & Candidates. NECO VIP group is where all NECO Questions and Answers are dropped at midnight before the stated exam time on the timetable.

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Today’s NECO Practical Chemistry Answers: (2020 Answers)

————————————————————————————–

Note: The answers below are not today’s answers.

2021 NECO Practical Chemistry answers loading…

(1) (2020 Answers)
Indicator used is methyl orange.
Volume of pipette used is 25cm³

Tabulate.
Titration; Rough|1st|2nd|3rd|

Final burette reading cm³|23.50|23.00|23.00|33.00|

Initial burette reading cm³| 00|0.00|0.00|10.00|

Volume of acid used(cm³) |23.50|23.00|23.00|23.00|

Average volume of A used = 23.00+23.00+23.00/3 =23.00cm³

Equation for the reaction
X²Co³(aq)+2HCl(aq)—->2XCl(aq)+H²O(s)+Cl(s)

(1i)
Concentration of A in moldm³ =concentration in gldm³.

3.6g of A =500cm²
Xg of A will be = 10000³
Xg=3.65*1000/500 =36.5/5 =7.3gldm³

Molar Mass of A HCl=1+35.5=36.5
Concentration of A =7.3gldm³/36.5gldm³
=0.20moldm³

(1ii)
Concentration of B in moldm³
concentration of A in moldm³ CA=0.20
Volume of used VA=23.00
Concentration of B in moldm³ CB=?
Volume of B used VB= 25.00

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CAVA/CBVB = n(A)/n(B) =2/1
0.20*23.00/CB*25.00=2/1

2*CB*25.00=0.20*23.00*1
CB=0.20*23.00/50
Cb=46/50=0.092moldm-³

(1iii)
Molar mass of B in glmol
Concentration of B(moldm-³)= conc gldm³/molar mass
0.092=10.60gldm³/molar mass
0.092 * molar mass =10.60gldm³
Molar mass =10.60gldm³/0.092
=115.2glmd

(1iv)
Relative atomic mass of X in X²CO³
X²+12+3(16)=115.2
2x+12+48=115.2
2x+60=115.2
2x=115.2÷60
2x=55.2
x=55.2/2=276

(2ai)
Tabulate:
TEST: C + 5cm³ of distilled water and shake thoroughly. Divide the solutions into three portions.

OBSERVATION: A pale green solution results

INFERENCE: Salt is soluble

(2aii)
TEST: To the first portion add NaOH solution in drys

OBSERVATION: Dark green gelatinous was formed

INFERENCE: Fe²+ present

OBSERVATION; Dark green gelatinous was formed

INFERENCE; Fe²^+ present

(2iii)
TEST; then in excess

OBSERVATION; precipitate is insoluble

INFERENCE; Fe²^+ present

(2iii)
TEST; To the second portion add K3Fe(CN)6 solution

OBSERVATION; A dark blue precipitate formed

INFERENCE; Fe²^+ confirmed

2aiii)
TEST: then in excess

OBSERVATION: Precipitate is insoluble

INFERENCE: Fe²+ present

(2aiv)
TEST: To the second portion add K3Fe(CN)6 solution

OBSERVATION: A dark blue precipitate formed

INFERENCE: Fe²+ confirmed

(2bi)
TEST: To the third portion add AgNO³ solution

OBSERVATION: White Precipitate formed

INFERENCE: SO4²- , CL-, CO²- present

(2bii)
TEST: To the results obtained in add dilute HNO3 in drops , then excess

OBSERVATION: White Precipitate is insoluble

INFERENCE: CL- present

(2biii)
TEST: To the results obtained in add NH3 solution

OBSERVATION: White Precipitate dissolves

INFERENCE: CL- Confirmed

(2iv)
TEST; To the third portion add AgNO³ solution

OBSERVATION; White Precipitate formed

INFERENCE; SO4²^- , CL^- CO²^- present

(2v)
TEST; To the results obtained in add dilute HNO3 in drops , then excess

OBSERVATION; White Precipitate is insoluble

INFERENCE; CL^- present

(2vi)
TEST; To the results obtained in add NH3 solution

OBSERVATION; White Precipitate dissolves

INFERENCE; CL^- Confirmed

(3ai)
Filtration

(3aii)
Diagram.

(3bi)
I. Methyl Orange
II. Methyl orange
III. Phenolphthalein

(3bii)
A white precipitate is observed. Effervescence occurs a gas is evolved which change lime water milky.

CHEMISTRY PRACTICAL SPECIMEN:

Requirements:
(a) One burette (50cm³)
(b) One pippete (20cm³/25cm³). However, all
candidates in a center must use pipettes of the
same volume.
(c) The usual apparatus and reagents for
qualitative work including:
(i) Dilute sodium hydroxide solution
(ii) Dilute ammonia solution
(iii) Dilute hydrochloric acid
(iv) Barium chloride solution
(v) Distilled water
(vi) Red and Blue litmus paper
(vii) Phenolphtalein
(d) Methyl orange
(e) One boiling tube
(f) Five test tubes
(g) Filtration apparatus
(h) Source of heat
Each candidate should be supplied with the
following: Labelled An, Bn, Cn, where ‘n’ is the
candidate’s serial number.
(a) 150cm³ of chloride acid solution in a bottle
labelled “An”. The acid solution which should
be the same for all candidates will contain
3.4cm³ of the concentrated hydrochloric acid
per dm³ solution.
(b) 150cm³ of sodium hydroxide solution in a
bottle labelled “Bn”. The solution which should
be the same for all candidates will contain
4.0g of sodium hydroxide per dm³ of solution.
(c) One spatulaful of copper (ii)
tetraoxosulphate (vi) salt in a specimen bottle
labelled “Cn”.

The questions below are strictly for practice not the 2021 Chemistry expo.

All your burette readings (initials and final) as well as the size of your pipette must be recorded but no account of experimented procedure is required. All calculations must be done in your booklet.

  1. A is O.200 moldm3 of HCI. C is a solution containing 14/3g of Na2CO3. x H2O in 500 cm3 of solution. (a) Put A into the burette and titrate it against 20.0 cm3 or 25.0 cm3 portions of C using methyl orange as indicator. Repeat the titration to obtain Consistent titre values. Tabulate your results and calculate the average volume of A used. The equation for the reaction is: Na2CO3 x H2O + 2HCL(aq) → 2NaCI(aq) + CO2(g) + (x+1) H2O(I).

(b) From your results and the information provided. Calculate the: (i) concentration of C in moldm-3; (ii) concentration of C in gdm-3; (iii) molar mass of Na2CO3, xH2O; (iv) the value of x in Na2CO3 xH2O. [H = 1.0; C=12.0; O = 16.0; Na =23.0]

Credit will be given for strict adherence to the instruction, for observations precisely recorded and for accurate inferences. All tests, observations and influences must be clearly entered in the booklet in ink at the same time they are made.

2. F is a mixture to two inorganic salts. Carry out the following exercise on F. record your observation and identify any gas(s) evolved. State the conclusions you draw from the result of each test. (a) Put all of F in a beaker and add about 10cm3 of distilled water. Stir well and filter. Keep the filtrate and the residue. (b)(i) To about 2cm3 of the filtrate, add NaOH(aq) in drops and then in excess (ii) To another 2cm3 portion of the solution, add a few drops of NHO3(aq)followed by few drops of AgNO3(aq). (d)(i) Put all the residue into a clean test-tube and add NHO3(aq) followed by few solution from 2(d)(i) add NaOH(aq) in drops and then in excess.

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3. State what would be observed if the following reactions are carried out in the laboratory: (i) methyl orange is dropped into a solution of lime juice (ii) hydrogen sulphide gas is bubbled through iron (III) chloride solution; (iii) sulphur (IV) oxide gas is bubbled into acidified solution of KMnO4; (iv) ethanoic acid is added to a solution of K2CO3.

CHEMISTRY PRACTICALS ANSWERS

  1. Indicator                                 =          Methyl Orange

Volume of the base used        =          25.00cm3

Titration Rough Titre 1st Titre 2nd Titre 3rd Titre
Final Burette readings cm3 24.70 24.80 24.70 24.90
Initial Burette reading cm3 0.00 0.00 0.00 0.00
Volume of acid used cm3 24.70 24.80 24.90 24.90

Average Titre              =          1st + 2nd + 3rd/3

=          24.80 + 24.70 + 24.90/3

=          24.80cm3

Alternatively 2 concordant titres can be used to calculate average titre.

Equation of the reaction: Na2CO3 XH2O + 2HCI(aq) → 2NacI(aq) + CO2(aq) + (x+1)H2O(I)

CAVA/CBVB     =  nA/nB

CA = Molar concentration of HCI(aq) in moldm3

VA = Volume of acid used in cm3 = 24.80cm3

CB = Molar concentration of Na2Cu3 xH2O in moldm3

nA = 2

nB = 1

(b)(i) concentration of C in moldm-3 = ? From the equation of reaction:

CAVA/CBVB     =  nA/nB

CA = 0.200 moldm3     VA = 24.80cm3

CB = ?                          VB = 25.00cm3

Substitution of known values

0.200 x 24.80/ CB x 25.00 = 2/1

CB = 1×0.200×24.80/2×25.00

C = 0.0992 moldm-3

(ii) Concentration of C in g dm-3 = ?

500cm2 → 14.3 g

1000cm3 →14.3/500 x 10002 g

= 28.6 g dm-3

(iii) Molar mass of Na2CO3 xH2O

Molar conc in moldm-3 = conc in g dm-3 / molar mass

Therefore: Molar mass g mol-1 = conc in g dm-3 / molar conc in moldm-3

= 28.6 g dm-3/0.0992 moldm-3

= 288.3065

Approximately 288 g mol-1

(iv) Value of x in Na2CO3 xH2O?

[H = 1.0, C = 12.0, O = 16.0, Na = 23.0]

Na2CO3 xH2O = 288

2(23) + 12 + 3 (16) + x (2(I) + 16) = 288

46 + 12 + 48 + 18x  = 288

106 + 18x        = 288

18x      = 288

18x      = 182

x       = 182/18

x       = 10.11

approximately 10

2 Test Observation Inference
(a) F + distil water + stir + filter Effervescence (bubbling) occurs, colourless and odourless gas evolved after filtration pale blue/colourless filtrate and green residue
(b)(i) Filtrate + NaOH(aq) in drops then in excess White precipitate formed   Precipitate insoluble in excess NaOH(aq) Ca2+/Pb2+   Ca2+ present
(b)(ii) Filtrate + NH3(aq) in drops then in excess No visible reaction   No visible reaction OR Ca2+ present   Ca2+ confirmed
(b)(i) Filtrate + NaOH(aq) in drops then in excess Blue gelatinous precipitate formed   Precipitate insoluble in excess     Cu2+  is present
(b)(ii) Filtrate + NH3(aq) in drops then in excess Pale (light) blue gelatinous precipitate formed   Precipitate dissolves to form a deep blue solution Cu2+     Cu2+  is confirmed
(c) Filtrate + NHO3(aq) + AgNO3(aq) No visible reaction No gas involved White precipitate formed CuI-  is present
(d)(i) Residue + HNO3(aq) Efferveness occurs, colourless and odourless gas evolves that turn blue litmus paper to red and turns lime water milky CO2(g) CO32- present
(d)(ii) Solution from 2(d)(i) + NaOH(aq) in drops then in excess Blue precipitate formed   Precipitate insoluble in excess NaOH(aq) Cu2+    Cu2+   present

3 (a)(i) Solution of lime juice turns to pink or red. (ii) The FeCI3 solution changes colour from brown to green and a yellow deposit. (iii) The purple colour of the KMnO4 solution turns colourless or decolourised. (iv) The solution of K2CO3 reacts with the addition of ethanoic acid to evolve a colourless, odourless gas with bubbling of effervescence.

If you have any questions about the 2021 NECO Chemistry Practical questions and answers, kindly let us know in the comment box.

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